Відео

HC Verma is a proud person and a very arrogant personality, he came to Patna and when the students came to salute him, he scolded them very badly, he may be good to everyone but I always think about his personality that day, a learned teacher professor does not have a way of speaking and while he came to Patna for a day, the students went to see him by donating 1000 rupees for a one day function, he repaid them by scolding them, if I ever meet him now, I will definitely ask him sir, in your eyes only the children of rich people are good, the children of poor have no importance, sir, I am really sorry for that nature of yours till date, may God give you the wisdom to behave well with all the children along with manners,

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❤IIT BOMBAY ❤

NAMSTE SIR❤ i love your teaching style. and sir you are the great teacher.i have no word to express my feelings ❤😊 salute sir. recently i am in class 10 sir,1ne day i will crack iit after cracking i will meet u sir . please suggest me some gyan so i can become successful person❤.

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Sir but if you take theta 1 slightly positive and theta 2 slightly less than 90 then product of their slopes is not equal to -1 bcz both have positive slope and two positive cant hav a negative ans means idhr discontinuty h,,, plz consider my query

ua-cam.com/video/DbJOUBqdLiw/v-deo.html

After completing 12th,today i came to know why tan90 is undefined..

Kya jamana hai physics ke nam pe behudapan karne wale log millions me view pata hai...or H.C.VERMA sir ke vedios par 1 million view bhi nahi hota.... durbhagya hai is desh ka..

Love from Pakistan

7:31 the force which acting towards the center of circular path is called centrifugal force

sir i am currently in class 12th and I will be getting into iit delhi cse next year for sure and hope to meet you one day

Hello sir i am priyanshu garg and my doubt is **can we control on the speed of time**is it possible.

2019 btech passout still having his two books in my collection

lob you sir 💖💖💖💖💖💖💖💖💖💖

Pe sir mai to arts wala hoon 😂

It depends on how the drift velocity is defined in wiki and few texts it is defined as : drift velocity is the average velocity attained by charged particles, such as electrons, in a material due to an electric field. under a force, the velocity attained is 'at' for the eqation 'v = u +at' with u as 0. in between every collition it is this velocity that is attained by the electron, many such collisions and many such in between period, the average of it is 'a*tou' where tou = average time between collitions. so by definition Vd = a*tou what it is not is the distance traveled by electron by time over long period. u can seperately define it that way but the two definations are different. this second way of definition is used by H.C. Verma which makes sense, but as it is different from the first one, it will give different results. also it becomes a little bit complicated to get exact expression and needs bit more assumption in the second way as the focus is on distance traveled, you use 's = ut + 1/2 a t^2' to calulate the distance traveled between each collitions. so 's1 = 1/2 a t1^2' now add all this s1 s2 upto sn to get '1/2 a * (t1^2 + t2^2 + ....)/(t1 + t2 + ....)' and now to simplify it further u have to use more assumption like t1 = t2 = .... = tuo. this is again not necessary as it can also be assumed that t1, t2, ..... so may be taken from some other destribution like normal destribution which may make better sense but will give different result(final expression). the first feinition cuts out all this complications and straing way defines as the velocity attained making the expression easy to calculate, but we can not use it to calculate the distance covered by electron, the secaond way is focused to calculate the distance drifted by electron but is difficult to calculate and needs more assumptions like distribution of the time intervels. but then again as H C Verma said if u want to calculate rigorously than we have to use quantum mechanics as electrons are not tiny balls and we can not apply kinematics in this simplified form.

Sir I am a 2026 jee aspirant currently in class 11 can you please guide us with a good suggestion you have

This is the father of physics . I offered huge respect for HC Verma

Sir your smile is so beautiful ❤❤❤

Sir, I liked your explanation about this seemingly innocuous question, using the idea of limits for the angle of a line near the y-axis I.e. /theta-1 approaching from the 2nd quadrant, and the corresponding angle /theta_2 of a line near the x-axis in the 1st quadrant, making the product tan /theta_1 x tan/theta_2 clearly negative. What if we approach the limit of the above angles /theta1 &/theta_2 both in the 1st quadrant ---->> to zero i.e. approaching the x and y axes simultaneously. Then the product tan/theta_1 x tan/theta _2 will be POSITVE isn't it Sir? Can you explain this possible case also please?

I asked question thank you sir 😂

wow i really enjoyed learning from u sir.

Legend are focusing on HC Verma Sir not on question 😅😅

As simple as that you can't assume , collision time for each individual collision is tau, because it is simply illogical and only a hypothetical situation. You have to admit that.

Sir q1 ko PATA chal gya 😂 future se aya hu

Anyone in 2024 😊

Left side 0=1 wala question लगा hai 😂😂😂😂 sir ne mitaya nhi😊

I'm a JEE student in Motion institute and fully respect HC Verma Sir as I respect NV Sir. 👍❤❤

Sir i have a doubt.. what is the reason behind keeping long hair ?

Why this video is so short 😢?

Sir I am having a doubt in QUESTIONS FOR SHORT ANSWER 16 from your book concept of physics volume 1 chapter 10 (rotation mechanics) According to me as the weights are equal along with the perpendicular distance of application of force(here gravity) from the axis of rotation(considering that the weighing machine has a central rod and 2 threads tied at end and one at centre)so torque due to the weight will be equal and it will remain in rotational equilibrium But if this happens how we can say that it is measuring the right weight as in this case it is showing two equal weights unequal

Super explanation ❤

Thank you a lot sir. If we learn with such logics and supporting maths everything in science has a meaning and will be useful I feel.

Coordinate geometry, compounding, geometric progression, algebra, calculus, graph, common sense taught in one topic

Sir what is the charge on a capacitor . Sir Q or zero

Great explanation sir , I always find a bundle of joy in learning these types of questions and concepts.

♾️+0 =n+ ♾️= ❓. ❤❤❤❤❤❤❤❤

Your analysis is wrong someway in previous videos

sir , I am Nitesh from class 12 I am reading magnetic field due to electric current from your book concepts of physics part 2 When I read the ampere's law it states that the electric field should be constant in the loop . can you please explain this .I also search on internet but they talk about Maxwell's equations which I not studied yet.

Good morning sir, Sir please solve my dobut how current flows through a wire and in which direction ?

You are so simple sir 🫡

How much they are lucky who are being taught by respected sir ❤.

Sir meri physics thodi weak hai kaya karu jinta time muje chemistry aur math mai nahi lagta utna physics mai lag jaata hai

Please solve this problem. Suppose a small solid ball of density ρ, mass m and radius r is dropped in a liquid of density d and viscosity coffecient η. Acceleration due to gravity is g. Now the body will fall in the liquid. Soon it will reach its terminal speed. But suppose we have to establish a relation between the velocity of the ball and time before it reaches its terminal velocity. So, let the velocity of the ball be v before it reaches its terminal speed. At this moment, the net force on the ball will be given by Net force (downward) = weight of the ball - upthrust - viscous force m (dv/dt) = mg - (volume of the ball x dg) - 6πηrv Putting m = 4πr³ρ/3 and volume of the ball = 4πr³/3, we get dv/dt = g - (dg/ρ) - 9ηv/2r²ρ This is a differtial equation. It can be easily solved. The value of integration constant can be found by putting v=0 when t=0. So its final solution is, [ 2r²(ρ-d)g ] v = ----------------------- [ 1 - {e^(-9ηt/2r²ρ)} ] 9η In the equation above, e is the exponential constant and t is time. This equation describes how the velocity of the ball changes over time before the ball reaches its terminal velocity. Putting t = infinity i.e. t = ♾️, the above equation reduces to, [ 2r²(ρ-d)g ] v = ------------------------ 9η This is our well known result that is known as the expression of terminal velocity. Bro! From equation (1) we can find how long the ball will take to reach its terminal speed. What we have to do in order to find it is just putting the value of terminal speed in the left hand side of the equation. So let's put it. When we do it, the expression of terminal velocity in LHS will be cancelled by the expression of terminal velocity in RHS. So what we will be left with will be -- 1 = 1 - e^(-9ηt/2r²ρ) ➡ e^(-9ηt/2r²ρ) = 0 ➡ e^(9ηt/2r²ρ) = ♾️ ➡ t = ♾️ And this result is crazy because it left me with what I didn't want to calculate. Actually I want to develop an expression for the minimum time the ball will take to reach its terminal velocity but the result says, the velocity of the ball will be equal to terminal velocity at t = ♾️. The result is absolutely correct but i want to know if there exists a way so I can develop an expression for the minimum time the ball will take to reach terminal velocity. If we assume when t = 0 then v=u (where u is the initial velocity) in order to find a different value of the integration constant then our equation looks like -- g - (dg/ρ) - (9ηu/2r²ρ) e^(9ηt/2r²ρ) = ------------------------------------------- g - (dg/ρ) - (9ηv/2r²ρ) If we put the expression of terminal velocity in this equation to find the time at which the ball reaches at its terminal velocity then the right hand side of the equation becomes infinite and we get, e^(9ηt/2r²ρ) = ♾️ ➡ t = ♾️ Again the same result! Is there no way to find the time or the minimum time the ball takes to achieve terminal velocity? The result, the velocity of the ball is terminal at t = ♾️, is useless for us because we already know it.

Namaskar sir , I have a doubt in properties of electric charge . It is mentioned that motion of a body doesn't impact it's charge but the prblm is that sir , according to Einstein special theory of relativity, Mass varies with is speed . So sir , if we suppose move any body with speed of light and if we found there is some defect of mass ,means loss in atoms . Then how in this situation,charge does being affected although there is loss of atoms ? . With due respect sir .

Great sir

Interactive teacher + chalk board = real interactive board 👏 Huge respect for you sir ❤

Wowww❤

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